三角函数1高二数学教案
日期:2010-11-17 11:33
cos2α,cos2α,求sin2α,cos2α,tan2α已知tanα=-2,tan2α已知sinα=,且,cos2α,求tan2α,倍角公式复习题姓名:______学号:___成绩:__________填空:sin2α=__________cos2α=__________=__________=__________tan2α=__________2sin___cos___=sin4αcos25α-sin25α=cos______=tan______________________________=________=_________=________=________=________1-2sin2735°=________=________=________=________计算:已知sinα=06,且,求sin2α,tan2α已知cosα=,tan2α已知cosα=,且α是锐角,求sin2α,求sin2α,且,cot2α,
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